25x^2+25x=-6

Solution for 25x^2+25x=-6 equation:

25x^2+25x=-6

We move all terms to the left:

25x^2+25x-(-6)=0

We add all the numbers together, and all the variables

25x^2+25x+6=0

a = 25; b = 25; c = +6;
Δ = b2-4ac
Δ = 252-4·25·6
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-5}{2*25}=\frac{-30}{50}
=-3/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+5}{2*25}=\frac{-20}{50}
=-2/5
$